The bounce of a Squash Ball Essay Example for Free

The bounce of a Squash Ball Essay However, some energy is lost as due to friction between the molecules in the air, and the surface of the ball. 3 This is during the time where the ball is in contact with the floor. There are really three stages here, I will show them below: i) ii) iii) In i, the ball has hit the ground, and because of inertia, the ball tries to keep moving and cant because the ground beneath it is solid. This causes the ball to change to a sort of oval shape, this change of shape causes some energy to be lost as heat and the kinetic energy to become Elastic Energy. Also, the ball hitting the ground will cause some energy to go on as sound and some will be sent through the surface as a wave. In ii, the ball is still, and has no energy other than Elastic Energy; it is exactly between i and iii. In iii, The Elastic Energy is being converted to Kinetic Energy, and causes the ball to go from the oval shape, back to its original shape, and bounces off of the ground. The Elastic Energy in the ball is now becoming Kinetic Energy again and the reshaping of the ball causes some more energy to be lost as heat. 4 Here the ball is going back up after bouncing off of the ground. The ball has Kinetic Energy, and again some energy is lost as heat due to friction between the air and the ball. 5 At this stage, the ball is stationary in the air because gravity has prevented it from rising any further. However, the ball is not as high as it was when it was dropped; this is because some energy was lost as heat. This stage links back to stage two repeatedly, until all of the energy from the ball has been lost, at which point it will become stationary on the ground. Prediction With this in mind, I am predicting that the higher the ball is dropped from, the higher it will bounce (due to increased energy). However, I predict that the ball will never reach the height it fell from because of energy which is lost as heat from friction and sound when it hits the ground. Calculating Epg The formula mgh (or Mass   Gravity   Height) will show the amount of Gravitational Potential Energy (Epg) the ball has at this stage. The mass of our ball was 0. 024 kg, which is constant (it doesnt change). The gravity here on Earth is 10N per kg of mass, for our ball this would mean 0. 24N, another constant. The height from which we drop the ball is a variable. Therefore to work out the Epg of the ball at any given height we would use the formula Height. We can shorten this to 0. 006 because mass and gravity are constant. For example, if we wanted to know how much Epg the ball had when held at 1. 00 m, we would do 0. 006 1. 00, which is 0. 006. The reason for calculating Epg is so that later on the kinetic energy (Ek) of the ball can be calculating, in turn allowing the velocity of the ball upon impact to be calculated. Method First of all, two metre sticks were placed vertically against a wall, one above the other, creating a makeshift double-metre stick, this was held against the wall. Next, the ball was held so that the bottom of it was aligned with the height (e. g. 1. 00 m). Meanwhile, another member of the team laid on the floor, facing the metre stick. The ball was then released when the member on the floor was ready. When the ball bounced up the member on the floor noted it down. This was repeated five times for each drop height (0. 8m, 1. 0m, 1. 2m, etc up to 2. 0m). After each drop height was done five times, the ball was heated to 40 degrees Celsius in a water bath. Our variable was the drop height of the ball. We chose the range 0. 6m 2. 0m because it achieves a good set of results, while not taking too much time after dropping from each height five times. We dropped the ball five times from each height and then obtained an average to try and get a good range of results, and also to eliminate anomalous results from our graphs. Results Table Drop Height (m) Gravitational Potential Energy (J) Bounce Height (m) Speed on Impact (m/sec) ms Analysis. The results in this table show that the Epg increases when the ball is held higher up. It also shows that the ball bounces higher when the drop height is higher, and that the ball will never bounce to the same height it was dropped from. One other thing my table shows is that the higher the drop height, the higher the speed of the ball on impact with the ground. This proves everything I predicted to be correct, and also correlates with my energy transfer diagram, which is what I based my prediction on. Ball Speed Epg = Ek on impact. To work out the velocity (speed) of the ball on impact we would use the formula v=VEk. First we need to know the value of Ek which is dependant on Evaluation There are just two anomalies, they are at 1. 4m and 1. 6m, they is quite far from the line of best fit. I believe the cause was human error perhaps in the inaccuracy of trying to see how high the ball was in a fraction of a second. If I had the chance to repeat this investigation, I would improve the procedure by improving the measuring system, perhaps by using a digital video camera to record how high the ball bounced and then playing it back frame by frame on a computer because it is very hard to see where the ball is in a fraction of a second with human eyesight. I would increase the range of results to be from 0. 2m maybe 5. 0m, because it would give a much larger range, in which perhaps the rule of the ball bouncing higher when dropped from higher would be incorrect.